Query 1 :

In a direct variation y = 12 when x = 2. Write the direct variation equation that reveals the connection between x and y.

Query 2 :

In a direct variation y = 300 when x = 5. Write the direct variation equation that reveals the connection between x and y.

Query 3 :

In a direct variation y = 12 when x = 40. Write the direct variation equation that reveals the connection between x and y.

Query 4 :

In a direct variation y = 4 when x = 15. Write the direct variation equation that reveals the connection between x and y.

Query 5 :

In a direct variation y = 48 when x = 16. Write the direct variation equation that reveals the connection between x and y.

## Solutions

1. Reply :

Equation of direct variation :

y = kx —–(1)

Substitute x = 2 and y = 12.

12 = ok(2)

12 = 2k

Divide all sides by 2.

6 = ok

Substitute ok = 1 in (1)

y = 6x

2. Reply :

Equation of direct variation :

y = kx —–(1)

Substitute x = 5 and y = 300.

300 = ok(5)

300 = 5k

Divide all sides by 5.

60 = ok

Substitute ok = 60 in (1).

y = 60x

3. Reply :

Equation of direct variation :

y = kx —–(1)

Substitute x = 40 and y = 12.

40 = ok(12)

40 = 12k

Divide all sides by 12.

10/3 = ok

Substitute ok = 10/3 in (1).

y = (10/3)x

4. Reply :

Equation of direct variation :

y = kx —–(1)

Substitute x = 15 and y = 4.

4 = ok(15)

4 = 15k

Divide all sides by 15.

4/15 = ok

Substitute ok = 4/15 in (1).

y = (4/15)x

5. Reply :

Equation of direct variation :

y = kx —–(1)

Substitute x = 16 and y = 48.

48 = ok(16)

48 = 16k

Divide all sides by 16.

3 = ok

Substitute ok = 3 in (1).

y = 3x

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