Trigonometric identities are equalities the place we’d have trigonometric features and they might be true for each worth of the occurring variables. Geometrically, these are identities involving sure features of a number of angles.

## SOHCAHTOA

Sinθ = Reverse facet/Hypotenuse facet

Cosθ = Adjoining facet/Hypotenuse facet

Tanθ = Reverse facet/Adjoining facet

Cscθ = Hypotenuse facet/Reverse facet

Secθ = Hypotenuse facet/Adjoining facet

Cotθ = Adjoining facet/Reverse facet

## Reciprocal Trigonometric Identities

sinθ = 1/cscθ

cscθ = 1/sinθ

cosθ = 1/secθ

secθ = 1/cosθ

tanθ = 1/cotθ

cotθ = 1/tanθ

## Different Trigonometric Identities

sin^{2}θ + cos^{2}θ = 1

sin^{2}θ = 1 – cos^{2}θ

cos^{2}θ = 1 – sin^{2}θ

sec^{2}θ – tan^{2}θ = 1

sec^{2}θ = 1 + tan^{2}θ

tan^{2}θ = sec^{2}θ – 1

csc^{2}θ – cot^{2}θ = 1

csc^{2}θ = 1 + cot^{2}θ

cot^{2}θ = csc^{2}θ – 1

## Compound Angles Identities

sin(A + B) = sinAcosB + cosAsinB

sin(A + B) = sinAcosB + cosAsinB

cos(A + B) = cosAcosB – sinAsinB

cos(A – B) = cosAcosB + sinAsinB

tan(A + B) = (tanA + tanB)/(1 – tanAtanB)

tan(A – B) = (tanA – tanB)/(1 + tanAtanB)

## Double Angle Identities

sin2A = 2sinAcosA

cos2A = cos^{2}A – sin^{2}A

tan2A = 2tanA/(1 – tan^{2}A)

cos2A = 1 – 2sin^{2}A

cos2A = 2cos^{2}A – 1

sin2A = 2tanA/(1 + tan^{2}A)

cos2A = (1 – tan^{2}A)/(1 + tan^{2}A)

sin^{2}A = (1 – cos2A)/2

cos^{2}A = (1 + cos2A)/2

## Half Angle Identities

sinA = 2sin(A/2)cos(A/2)

cosA = cos^{2}(A/2) – sin)^{2}(A/2)

tanA = 2tan(A/2)/[1 – tan^{2}(A/2)]

cosA = 1 – 2sin^{2}(A/2)

cosA = 2cos^{2}(A/2) – 1

sinA = 2tan(A/2)/[1 + tan^{2}(A/2)]

ccosA = [1 – tan^{2}(A/2)]/[1 + tan^{2}(A/2)]

sin^{2}(A/2) = (1 – cosA)/2

ccos^{2}(A/2) = (1 + cosA)/2

tan^{2}(A/2) = (1 – cosA)/(1 + cosA)

## Triple Angle Identities

sin3A = 3sinA – 4sin^{3}A

cos3A = 4cos^{3}A – 3cosA

tan3A = (3tanA – tan^{3}A)/(1 – 3tan^{2}A)

## Sum to Product Identities

sinC + sinD = 2sin[(C + D)/2]2cos[(C – D)/2]

sinC – sinD = 2cos[(C + D)/2]sin[(C – D)/2]

cosC + cosD = 2cos[(C + D)/2]cos[(C – D)/2]

cosC – cosD = 2sin[(C + D)/2] ⋅ sin[(C – D)/2]

## Values of Trigonometric Ratios for Normal Angles

## Fixing Phrase Issues Utilizing Trigonometric Identities

Step 1 :

Understanding the query and drawing the suitable diagram are the 2 most essential issues to be achieved in fixing phrase issues in trigonometry.

Step 2 :

Whether it is doable, we have now to separate the given data. As a result of, once we break up the given data in to components, we will perceive them simply.

Step 3 :

We’ve to attract diagram nearly for all the phrase issues in trigonometry. The diagram we draw for the given data have to be right. Drawing diagram for the given data will give us a transparent understanding in regards to the query.

Step 4 :

As soon as we perceive the given data clearly and proper diagram is drawn, fixing phrase issues in trigonometry wouldn’t be a difficult work.

Step 5 :

After having drawn the suitable diagram primarily based on the given data, we have now to provide title for every place of the diagram utilizing English alphabets (it’s clearly proven within the phrase downside given under). Giving title for the positions could be simpler for us to determine the components of the diagram.

Step 6 :

Now we have now to make use of one of many three trigonometric ratios (sin, cos and tan) to search out the unknown facet or angle.

As soon as the diagram is drawn and we have now translated the English Assertion (data) given within the query as mathematical equation utilizing trigonometric ratios appropriately, 90% of the work will probably be over. The remaining 10% is simply getting the reply. That’s fixing for the unknown.

These are essentially the most generally steps concerned in fixing phrase issues in trigonometry.

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