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# Phrase Issues on Fraction | Math Fraction Phrase Issues |Fraction Math

In phrase issues on fraction we are going to resolve differing types
of issues on multiplication of fractional numbers and division of fractional
numbers.

1. 4/7 of a quantity is 84. Discover the quantity.

Resolution:

In line with the issue,

4/7 of a quantity = 84

Quantity = 84 × 7/4

[Here we need to multiply 84 by the reciprocal of 4/7] = 21 × 7

= 147

Subsequently, the quantity is 147.

2. Rachel took (frac{1}{2}) hour to color a desk and (frac{1}{3})
hour to color a chair. How a lot time did she soak up all?

Time taken to color a desk =
(frac{1}{2}) hour

Time taken to color a chair =
(frac{1}{3}) hour

Complete time taken                =
(frac{1}{2}) hour + (frac{1}{3}) hour

(frac{1}{2}) + (frac{1}{3}) = (frac{3}{6}) + (frac{2}{6})

=
(frac{5}{6}) hour

(frac{1 × 3}{2 × 3}) = (frac{3}{6}) ; L.C.M. of two, 3
is 6.

(frac{1 × 2}{3 × 2}) = (frac{2}{6})

3. If 3(frac{1}{2}) m of wire is minimize from a chunk of 10 m
lengthy wire, how a lot of wire is left?

Complete size of the wire = 10 m

Fraction of the wire minimize out = 3(frac{1}{2}) m = (frac{7}{2})
m

Size of the wire left = 10 m – 3(frac{1}{2}) m

= [(frac{10}{1}) – (frac{7}{2})]
L.C.M. of 1, 2 is 2

= [(frac{20}{2}) – (frac{7}{2})]
m        (frac{10}{1})

= [(frac{20 – 7}{2})] m

= (frac{13}{2}) m

= 6(frac{1}{2}) m

4. One half of the scholars in a college are ladies, 3/5 of
these ladies are learning in decrease lessons. What fraction of ladies are learning
in decrease lessons?

Resolution:

Fraction of ladies learning at school = 1/2

Fraction of ladies learning in decrease lessons = 3/5 of 1/2

=
3/5 × 1/2

=
3 × 1/5 × 2

=
3/10

Subsequently, 3/10 of ladies learning in decrease lessons.

5. Maddy reads three-fifth of 75 pages of his lesson. What number of extra pages he want to finish the lesson?

Resolution:

= 3/5 × 75 = 45 pages.

Maddy has to learn = 75 – 45.

= 30 pages.

Subsequently, Maddy has to learn 30 extra pages.

6. A herd of cows provides 4 litres of milk every day. However every cow provides one-third of complete milk every day. They provide 24 litres milk in six days. What number of cows are there within the herd?

Resolution:

A herd of cows provides 4 litres of milk every day.

Every cow provides one-third of complete milk every day = 1/3 of 4

Subsequently, every cow provides 4/3 of milk every day.

Complete no. of cows = 4 ÷ 4/3

= 4 × ¾

= 3

Subsequently there are 3 cows within the herd.

Questions and Solutions on Phrase issues on Fractions:

1. Shelly walked (frac{1}{3}) km. Kelly walked (frac{4}{15})
km. Who walked farther? How a lot farther did one stroll than the opposite?

2. A frog took three jumps. The primary soar was (frac{2}{3})
m lengthy, the second was (frac{5}{6}) m lengthy and the third was (frac{1}{3})
m lengthy. How far did the frog soar in all?

3. A vessel comprises 1(frac{1}{2}) l of milk. John drinks
(frac{1}{4}) l of milk; Joe drinks (frac{1}{2}) l of milk. How a lot of
milk is left within the vessel?

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