In phrase issues on fraction we are going to resolve differing types

of issues on multiplication of fractional numbers and division of fractional

numbers.

**1.** 4/7 of a quantity is 84. Discover the quantity.

**Resolution:**

In line with the issue,

4/7 of a quantity = 84

Quantity = 84 × 7/4

[Here we need to multiply 84 by the reciprocal of 4/7]

= 21 × 7

= 147

Subsequently, the quantity is 147.

**2.** Rachel took (frac{1}{2}) hour to color a desk and (frac{1}{3})

hour to color a chair. How a lot time did she soak up all?

Time taken to color a desk =

(frac{1}{2}) hour

Time taken to color a chair =

(frac{1}{3}) hour

Complete time taken =

(frac{1}{2}) hour + (frac{1}{3}) hour

(frac{1}{2}) + (frac{1}{3}) = (frac{3}{6}) + (frac{2}{6})

=

(frac{5}{6}) hour

(frac{1 × 3}{2 × 3}) = (frac{3}{6}) ; L.C.M. of two, 3

is 6.

(frac{1 × 2}{3 × 2}) = (frac{2}{6})

**3.** If 3(frac{1}{2}) m of wire is minimize from a chunk of 10 m

lengthy wire, how a lot of wire is left?

Complete size of the wire = 10 m

Fraction of the wire minimize out = 3(frac{1}{2}) m = (frac{7}{2})

m

Size of the wire left = 10 m – 3(frac{1}{2}) m

= [(frac{10}{1}) – (frac{7}{2})]

L.C.M. of 1, 2 is 2

= [(frac{20}{2}) – (frac{7}{2})]

m (frac{10}{1})

= [(frac{20 – 7}{2})] m

= (frac{13}{2}) m

= 6(frac{1}{2}) m

**4.** One half of the scholars in a college are ladies, 3/5 of

these ladies are learning in decrease lessons. What fraction of ladies are learning

in decrease lessons?

**Resolution:**

Fraction of ladies learning at school = 1/2

Fraction of ladies learning in decrease lessons = 3/5 of 1/2

=

3/5 × 1/2

=

3 × 1/5 × 2

=

3/10

Subsequently, 3/10 of ladies learning in decrease lessons.

**5.** Maddy reads three-fifth of 75 pages of his lesson. What number of extra pages he want to finish the lesson?

**Resolution:**

Maddy reads = 3/5 of 75

= 3/5 × 75

= 45 pages.

Maddy has to learn = 75 – 45.

= 30 pages.

Subsequently, Maddy has to learn 30 extra pages.

**6.** A herd of cows provides 4 litres of milk every day. However every cow provides one-third of complete milk every day. They provide 24 litres milk in six days. What number of cows are there within the herd?

**Resolution:**

A herd of cows provides 4 litres of milk every day.

Every cow provides one-third of complete milk every day = 1/3 of 4

Subsequently, every cow provides 4/3 of milk every day.

Complete no. of cows = 4 ÷ 4/3

= 4 × ¾

= 3

Subsequently there are 3 cows within the herd.

Questions and Solutions on Phrase issues on Fractions:

**1.** Shelly walked (frac{1}{3}) km. Kelly walked (frac{4}{15})

km. Who walked farther? How a lot farther did one stroll than the opposite?

**2.** A frog took three jumps. The primary soar was (frac{2}{3})

m lengthy, the second was (frac{5}{6}) m lengthy and the third was (frac{1}{3})

m lengthy. How far did the frog soar in all?

**3.** A vessel comprises 1(frac{1}{2}) l of milk. John drinks

(frac{1}{4}) l of milk; Joe drinks (frac{1}{2}) l of milk. How a lot of

milk is left within the vessel?

**● ****Multiplication is Repeated Addition.**

**● ****Multiplication of Fractional Quantity by a Entire Quantity.**

**● ****Multiplication of a Fraction by Fraction.**

**● ****Properties of Multiplication of Fractional Numbers.**

**● ****Worksheet on Multiplication on Fraction.**

**● ****Division of a Fraction by a Entire Quantity.**

**● ****Division of a Fractional Quantity.**

**● ****Division of a Entire Quantity by a Fraction.**

**● ****Properties of Fractional Division.**

**● ****Worksheet on Division of Fractions.**

**● ****Simplification of Fractions.**

**● ****Worksheet on Simplification of Fractions.**

**● ****Worksheet on Phrase Issues on Fractions.**

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